C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 50 s\u1ed1 l\u00e0 m\u1ed9t c\u00e1ch ch\u01a1i kh\u00e1 m\u1edbi m\u1ebb \u0111\u1ed1i v\u1edbi anh ch\u1ecb em hi\u1ec7n nay. V\u1eady b\u1ea1n \u0111\u00e3 c\u00f3 kinh nghi\u1ec7m ch\u01a1i d\u00e0n \u0111\u1ec1 n\u00e0y ch\u01b0a. H\u00f4m nay t\u1ea1i b\u00e0i vi\u1ebft n\u00e0y xin gi\u1edbi thi\u1ec7u t\u1edbi c\u00e1c b\u1ea1n kinh nghi\u1ec7m ch\u01a1i \u0111\u1ec1 d\u00e0n b\u1ea5t b\u1ea1i v\u00e0 kh\u00f4ng \u0111\u1ec3 anh ch\u1ecb em ph\u1ea3i ch\u1edd l\u00e2u n\u1eefa gi\u1edd ch\u00fang ta h\u00e3y \u0111i v\u00e0o n\u1ed9i dung ch\u00ednh b\u00e0i chia s\u1ebb h\u00f4m nay nh\u00e9.<\/p>\n
D\u00e0n \u0111\u1ec1 50 s\u1ed1 l\u00e0 g\u00ec ?<\/strong><\/h2>\nD\u00e0n \u0111\u1ec1 50 s\u1ed1 l\u00e0 c\u00e1ch ch\u01a1i l\u00f4 \u0111\u1ec1 m\u00e0 b\u1ea1n c\u1ea7n ch\u1ecdn ra 50 con s\u1ed1 \u0111\u1ec3 ch\u01a1i \u0111\u1ec1 . C\u00e1ch ch\u01a1i n\u00e0y \u0111\u1ea3m b\u1ea3o t\u1ec9 l\u1ec7 b\u1ea1n tr\u00fang \u0111\u1ec1 cao nh\u1ea5t hi\u1ec7n nay \u0111ang \u00e1p d\u1ee5ng. \u0110\u00e2y \u0111\u01b0\u1ee3c xem l\u00e0 chuy\u00ean m\u1ee5c c\u00f3 t\u1ec9 l\u1ec7 chi\u1ebfn th\u1eafng cao nh\u1ea5t v\u00e0 \u1ed5n \u0111\u1ecbnh nh\u1ea5t hi\u1ec7n nay. V\u1edbi ph\u01b0\u01a1ng ph\u00e1p \u0111\u01b0a ra c\u00f9ng nghi\u00ean c\u1ee9u chuy\u00ean s\u00e2u \u0111\u1ebfn t\u1eeb c\u00e1c chuy\u00ean gia. Ch\u00fang t\u00f4i hi v\u1ecdng v\u1edbi kinh nghi\u1ec7m \u0111\u00e3 kh\u1eb3ng \u0111\u1ecbnh \u0111\u01b0\u1ee3c qua th\u1eddi gian. S\u1ebd gi\u00fap ph\u1ea7n n\u00e0o \u0111\u00f3 gi\u00fap anh ch\u1ecb em g\u1eb7t h\u00e1i th\u00e0nh c\u00f4ng m\u1ed7i ng\u00e0y.<\/p>\n
\n- \u01afU \u0111i\u1ec3m : \u0110\u1ed9 an to\u00e0n cao , x\u00e1c su\u1ea5t \u0111\u1ec1 v\u1ec1 l\u1edbn , t\u1ec9 l\u1ec7 chi\u1ebfn th\u1eafng \u1ed5n \u0111\u1ecbnh<\/li>\n
- Khuy\u1ebft \u0111i\u1ec3m : s\u1ed1 v\u1ed1n b\u1ecf ra nhi\u1ec1u ( khi b\u1ea1n ch\u01a1i nhi\u1ec1u s\u1ed1 )<\/li>\n<\/ul>\n
C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 50 s\u1ed1 b\u1ea5t b\u1ea1i<\/strong><\/h2>\nTuy \u0111\u00e2y \u0111\u01b0\u1ee3c xem l\u00e0 c\u00e1ch \u0111\u00e1nh an to\u00e0n nh\u01b0ng tr\u00ean th\u1ef1c t\u1ebf n\u00f3 l\u1ea1i r\u1ea5t m\u1ea1o hi\u1ec3m. M\u1ea1o hi\u1ec3m \u1edf \u0111\u00e2y ch\u00ednh l\u00e0 s\u1ed1 v\u1ed1n \u0111\u1ea7u t\u1eeb l\u00fac \u0111\u1ea7u b\u1ea1n ph\u1ea3i b\u1ecf ra kh\u00f4ng h\u00e8 nh\u1ecf nh\u01b0ng b\u00f9 l\u1ea1i x\u00e1c su\u1ea5t th\u1eafng s\u1ed1 \u0111\u1ec1 s\u1ebd cao h\u01a1n.<\/p>\n<\/figure>\n\u0110\u1ec3 gi\u1ea3m r\u1ee7i ro \u0111\u00e1nh d\u00e0n \u0111\u1ec1 50 con xu\u1ed1ng m\u1ee9c th\u1ea5p nh\u1ea5t m\u00e0 v\u1eabn \u0111\u1ea3m b\u1ea3o \u0111\u01b0\u1ee3c t\u00ednh hi\u1ec7u qu\u1ea3, c\u00e1c cao th\u1ee7 ch\u1ed1t s\u1ed1 \u0111\u00e3 ph\u00e2n t\u00edch \u01b0u, nh\u01b0\u1ee3c \u0111i\u1ec3m c\u1ee7a c\u00e1ch \u0111\u00e1nh n\u00e0y t\u1eeb \u0111\u00f3 l\u1ef1a ch\u1ecdn c\u00e1ch ch\u01a1i d\u00e0n \u0111\u1ec1 50 s\u1ed1 nu\u00f4i khung 3 ng\u00e0y l\u00e0 ph\u00f9 h\u1ee3p nh\u1ea5t. C\u00f9ng ch\u00fang t\u00f4i kh\u00e1m ph\u00e1 v\u1ec1 chi\u1ebfn thu\u1eadt ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y nh\u00e9.<\/p>\n
Ng\u00e0y 1<\/strong> : \u0111\u00e1nh m\u1ed7i con 10 ngh\u00ecn (10.000 vn\u0111 x 50 = 500.000 vn\u0111). N\u1ebfu \u0103n l\u1eddi 10 x 70.000 = 700.000 vn\u0111 \u2013 500.000 vn\u0111 = 200.000 vn\u0111.<\/p>\nNg\u00e0y 2<\/strong> : \u0111\u00e1nh m\u1ed7i con 30 ngh\u00ecn (30.000 vn\u0111 x 50 = 1.500.000 vn\u0111). N\u1ebfu \u0103n l\u1eddi 30 x 70.000 vn\u0111 = 2.100.000 vn\u0111 \u2013 1.500.000 vn\u0111 = 600.000 vn\u0111.<\/p>\nNg\u00e0y 3<\/strong> : \u0111\u00e1nh m\u1ed7i con 70 ngh\u00ecn (70.000 vn\u0111 x 50 = 3.500.000 vn\u0111. N\u1ebfu \u0103n l\u1eddi 70 x 70.000 vn\u0111 = 4.900.000 vn\u0111 \u2013 3.500.000 vn\u0111 = 1.400.000 vn\u0111.<\/p>\nTheo nh\u01b0 C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 50 s\u1ed1 m\u00e0 ch\u00fang t\u00f4i \u0111\u01b0a ra \u0111\u00e2y. T\u00ednh ra m\u1ed7i ng\u00e0y anh ch\u1ecb em s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c trung b\u00ecnh 300.000vnd. Nh\u01b0 v\u1eady ch\u01a1i trong v\u00f2ng 3 ng\u00e0y ch\u00fang ta s\u1ebd c\u00f3 s\u1ed1 l\u00e3i t\u01b0\u01a1ng \u1ee9ng . Tr\u00ean \u0111\u00e2y ch\u1ec9 l\u00e0 t\u00ednh ch\u1ea5t minh h\u1ecda v\u1edbi s\u1ed1 v\u1ed1n \u0111\u01b0\u1ee3c \u0111\u01b0a ra , v\u1eady n\u00ean anh ch\u1ecb em c\u0169ng n\u00ean c\u00e2n b\u1eb1ng s\u1ed1 v\u1ed1n m\u00ecnh b\u1ecf ra nh\u00e9. C\u00e1c b\u1ea1n c\u00f3 th\u1ec3 v\u00e0o ti\u1ec1n \u00edt h\u01a1n ho\u1eb7c nhi\u1ec1u h\u01a1n t\u00f9y v\u00e0o s\u1ed1 v\u1ed1n m\u00ecnh c\u00f3 nh\u00e9. Xin ch\u00fac anh ch\u1ecb em tham kh\u1ea3o vui v\u1ebb v\u00e0 g\u1eb7p nhi\u1ec1u may m\u1eafn ph\u00e1t t\u00e0i.<\/p>\n<\/div>\n<\/div>\n
soi c\u1ea7u cao c\u1ea5p mi\u1ec1n b\u1eafc<\/span><\/h3>\n
C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 50 s\u1ed1 b\u1ea5t b\u1ea1i<\/strong><\/h2>\nTuy \u0111\u00e2y \u0111\u01b0\u1ee3c xem l\u00e0 c\u00e1ch \u0111\u00e1nh an to\u00e0n nh\u01b0ng tr\u00ean th\u1ef1c t\u1ebf n\u00f3 l\u1ea1i r\u1ea5t m\u1ea1o hi\u1ec3m. M\u1ea1o hi\u1ec3m \u1edf \u0111\u00e2y ch\u00ednh l\u00e0 s\u1ed1 v\u1ed1n \u0111\u1ea7u t\u1eeb l\u00fac \u0111\u1ea7u b\u1ea1n ph\u1ea3i b\u1ecf ra kh\u00f4ng h\u00e8 nh\u1ecf nh\u01b0ng b\u00f9 l\u1ea1i x\u00e1c su\u1ea5t th\u1eafng s\u1ed1 \u0111\u1ec1 s\u1ebd cao h\u01a1n.<\/p>\n<\/figure>\n\u0110\u1ec3 gi\u1ea3m r\u1ee7i ro \u0111\u00e1nh d\u00e0n \u0111\u1ec1 50 con xu\u1ed1ng m\u1ee9c th\u1ea5p nh\u1ea5t m\u00e0 v\u1eabn \u0111\u1ea3m b\u1ea3o \u0111\u01b0\u1ee3c t\u00ednh hi\u1ec7u qu\u1ea3, c\u00e1c cao th\u1ee7 ch\u1ed1t s\u1ed1 \u0111\u00e3 ph\u00e2n t\u00edch \u01b0u, nh\u01b0\u1ee3c \u0111i\u1ec3m c\u1ee7a c\u00e1ch \u0111\u00e1nh n\u00e0y t\u1eeb \u0111\u00f3 l\u1ef1a ch\u1ecdn c\u00e1ch ch\u01a1i d\u00e0n \u0111\u1ec1 50 s\u1ed1 nu\u00f4i khung 3 ng\u00e0y l\u00e0 ph\u00f9 h\u1ee3p nh\u1ea5t. C\u00f9ng ch\u00fang t\u00f4i kh\u00e1m ph\u00e1 v\u1ec1 chi\u1ebfn thu\u1eadt ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y nh\u00e9.<\/p>\n
Ng\u00e0y 1<\/strong> : \u0111\u00e1nh m\u1ed7i con 10 ngh\u00ecn (10.000 vn\u0111 x 50 = 500.000 vn\u0111). N\u1ebfu \u0103n l\u1eddi 10 x 70.000 = 700.000 vn\u0111 \u2013 500.000 vn\u0111 = 200.000 vn\u0111.<\/p>\nNg\u00e0y 2<\/strong> : \u0111\u00e1nh m\u1ed7i con 30 ngh\u00ecn (30.000 vn\u0111 x 50 = 1.500.000 vn\u0111). N\u1ebfu \u0103n l\u1eddi 30 x 70.000 vn\u0111 = 2.100.000 vn\u0111 \u2013 1.500.000 vn\u0111 = 600.000 vn\u0111.<\/p>\nNg\u00e0y 3<\/strong> : \u0111\u00e1nh m\u1ed7i con 70 ngh\u00ecn (70.000 vn\u0111 x 50 = 3.500.000 vn\u0111. N\u1ebfu \u0103n l\u1eddi 70 x 70.000 vn\u0111 = 4.900.000 vn\u0111 \u2013 3.500.000 vn\u0111 = 1.400.000 vn\u0111.<\/p>\nTheo nh\u01b0 C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 50 s\u1ed1 m\u00e0 ch\u00fang t\u00f4i \u0111\u01b0a ra \u0111\u00e2y. T\u00ednh ra m\u1ed7i ng\u00e0y anh ch\u1ecb em s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c trung b\u00ecnh 300.000vnd. Nh\u01b0 v\u1eady ch\u01a1i trong v\u00f2ng 3 ng\u00e0y ch\u00fang ta s\u1ebd c\u00f3 s\u1ed1 l\u00e3i t\u01b0\u01a1ng \u1ee9ng . Tr\u00ean \u0111\u00e2y ch\u1ec9 l\u00e0 t\u00ednh ch\u1ea5t minh h\u1ecda v\u1edbi s\u1ed1 v\u1ed1n \u0111\u01b0\u1ee3c \u0111\u01b0a ra , v\u1eady n\u00ean anh ch\u1ecb em c\u0169ng n\u00ean c\u00e2n b\u1eb1ng s\u1ed1 v\u1ed1n m\u00ecnh b\u1ecf ra nh\u00e9. C\u00e1c b\u1ea1n c\u00f3 th\u1ec3 v\u00e0o ti\u1ec1n \u00edt h\u01a1n ho\u1eb7c nhi\u1ec1u h\u01a1n t\u00f9y v\u00e0o s\u1ed1 v\u1ed1n m\u00ecnh c\u00f3 nh\u00e9. Xin ch\u00fac anh ch\u1ecb em tham kh\u1ea3o vui v\u1ebb v\u00e0 g\u1eb7p nhi\u1ec1u may m\u1eafn ph\u00e1t t\u00e0i.<\/p>\n<\/div>\n<\/div>\n
soi c\u1ea7u cao c\u1ea5p mi\u1ec1n b\u1eafc<\/span><\/h3>\n
\u0110\u1ec3 gi\u1ea3m r\u1ee7i ro \u0111\u00e1nh d\u00e0n \u0111\u1ec1 50 con xu\u1ed1ng m\u1ee9c th\u1ea5p nh\u1ea5t m\u00e0 v\u1eabn \u0111\u1ea3m b\u1ea3o \u0111\u01b0\u1ee3c t\u00ednh hi\u1ec7u qu\u1ea3, c\u00e1c cao th\u1ee7 ch\u1ed1t s\u1ed1 \u0111\u00e3 ph\u00e2n t\u00edch \u01b0u, nh\u01b0\u1ee3c \u0111i\u1ec3m c\u1ee7a c\u00e1ch \u0111\u00e1nh n\u00e0y t\u1eeb \u0111\u00f3 l\u1ef1a ch\u1ecdn c\u00e1ch ch\u01a1i d\u00e0n \u0111\u1ec1 50 s\u1ed1 nu\u00f4i khung 3 ng\u00e0y l\u00e0 ph\u00f9 h\u1ee3p nh\u1ea5t. C\u00f9ng ch\u00fang t\u00f4i kh\u00e1m ph\u00e1 v\u1ec1 chi\u1ebfn thu\u1eadt ch\u01a1i l\u00f4 \u0111\u1ec1 n\u00e0y nh\u00e9.<\/p>\n
Ng\u00e0y 1<\/strong> : \u0111\u00e1nh m\u1ed7i con 10 ngh\u00ecn (10.000 vn\u0111 x 50 = 500.000 vn\u0111). N\u1ebfu \u0103n l\u1eddi 10 x 70.000 = 700.000 vn\u0111 \u2013 500.000 vn\u0111 = 200.000 vn\u0111.<\/p>\n Ng\u00e0y 2<\/strong> : \u0111\u00e1nh m\u1ed7i con 30 ngh\u00ecn (30.000 vn\u0111 x 50 = 1.500.000 vn\u0111). N\u1ebfu \u0103n l\u1eddi 30 x 70.000 vn\u0111 = 2.100.000 vn\u0111 \u2013 1.500.000 vn\u0111 = 600.000 vn\u0111.<\/p>\n Ng\u00e0y 3<\/strong> : \u0111\u00e1nh m\u1ed7i con 70 ngh\u00ecn (70.000 vn\u0111 x 50 = 3.500.000 vn\u0111. N\u1ebfu \u0103n l\u1eddi 70 x 70.000 vn\u0111 = 4.900.000 vn\u0111 \u2013 3.500.000 vn\u0111 = 1.400.000 vn\u0111.<\/p>\n Theo nh\u01b0 C\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 50 s\u1ed1 m\u00e0 ch\u00fang t\u00f4i \u0111\u01b0a ra \u0111\u00e2y. T\u00ednh ra m\u1ed7i ng\u00e0y anh ch\u1ecb em s\u1ebd l\u1eddi \u0111\u01b0\u1ee3c trung b\u00ecnh 300.000vnd. Nh\u01b0 v\u1eady ch\u01a1i trong v\u00f2ng 3 ng\u00e0y ch\u00fang ta s\u1ebd c\u00f3 s\u1ed1 l\u00e3i t\u01b0\u01a1ng \u1ee9ng . Tr\u00ean \u0111\u00e2y ch\u1ec9 l\u00e0 t\u00ednh ch\u1ea5t minh h\u1ecda v\u1edbi s\u1ed1 v\u1ed1n \u0111\u01b0\u1ee3c \u0111\u01b0a ra , v\u1eady n\u00ean anh ch\u1ecb em c\u0169ng n\u00ean c\u00e2n b\u1eb1ng s\u1ed1 v\u1ed1n m\u00ecnh b\u1ecf ra nh\u00e9. C\u00e1c b\u1ea1n c\u00f3 th\u1ec3 v\u00e0o ti\u1ec1n \u00edt h\u01a1n ho\u1eb7c nhi\u1ec1u h\u01a1n t\u00f9y v\u00e0o s\u1ed1 v\u1ed1n m\u00ecnh c\u00f3 nh\u00e9. Xin ch\u00fac anh ch\u1ecb em tham kh\u1ea3o vui v\u1ebb v\u00e0 g\u1eb7p nhi\u1ec1u may m\u1eafn ph\u00e1t t\u00e0i.<\/p>\n<\/div>\n<\/div>\nsoi c\u1ea7u cao c\u1ea5p mi\u1ec1n b\u1eafc<\/span><\/h3>\n