{"id":18386,"date":"2024-03-16T02:09:51","date_gmt":"2024-03-16T02:09:51","guid":{"rendered":"https:\/\/soicau3017.minhngocxoso.com\/?p=18386"},"modified":"2024-03-16T02:09:51","modified_gmt":"2024-03-16T02:09:51","slug":"so-da-mien-nam-danh-so-da-1-ngan-trung-bao-nhieu-tien","status":"publish","type":"post","link":"https:\/\/soicaurongbachkim666.com\/so-da-mien-nam-danh-so-da-1-ngan-trung-bao-nhieu-tien\/","title":{"rendered":"S\u1ed1 \u0111\u00e1 mi\u1ec1n Nam – \u0110\u00e1nh s\u1ed1 \u0111\u00e1 1 ng\u00e0n tr\u00fang bao nhi\u00eau ti\u1ec1n"},"content":{"rendered":"
Anh em ch\u01a1i s\u1ed1 mi\u1ec1n B\u1eafc c\u00f3 l\u1ebb \u00edt ng\u01b0\u1eddi bi\u1ebft \u0111\u1ebfn s\u1ed1 \u0111\u00e1, v\u00ec c\u00e1ch ch\u01a1i n\u00e0y th\u01b0\u1eddng \u0111\u01b0\u1ee3c th\u00f4ng d\u1ee5ng t\u1ea1i khu v\u1ef1c mi\u1ec1n Nam v\u00e0 Trung h\u01a1n l\u00e0 mi\u1ec1n B\u1eafc. D\u00f9 n\u00f3 c\u00f3 nhi\u1ec1u \u0111i\u1ec3m t\u01b0\u01a1ng \u0111\u1ed3ng v\u1edbi l\u00f4 xi\u00ean mb tuy nhi\u00ean s\u1ed1 \u0111\u00e1 mi\u1ec1n Nam v\u1eabn c\u00f3 gi\u1eef c\u00e1i ch\u1ea5t ri\u00eang c\u1ee7a m\u00ecnh. Ph\u1ea1m vi b\u00e0i vi\u1ebft s\u1ebd gi\u1edbi thi\u1ec7u kh\u00e1i ni\u1ec7m, c\u00e1ch t\u00ednh ti\u1ec1n khi ch\u01a1i v\u00e0 c\u00e1ch \u0111\u00e1nh s\u1ed1 \u0111\u00e1 mi\u1ec1n Nam sao cho chu\u1ea9n nh\u1ea5t.<\/span><\/p>\n N\u1ed9i dung:<\/span><\/p>\n – L\u00f4 \u0111\u00e1 c\u0169ng l\u00e0 m\u1ed9t t\u00ean g\u1ecdi kh\u00e1c c\u1ee7a s\u1ed1 \u0111\u00e1, c\u00e1ch ch\u01a1i n\u00e0y xu\u1ea5t ph\u00e1t t\u1eeb mi\u1ec1n Nam n\u01b0\u1edbc ta n\u00ean c\u00f3 nhi\u1ec1u ng\u01b0\u1eddi g\u1ecdi l\u00e0 s\u1ed1 \u0111\u00e1 mi\u1ec1n Nam. Hi\u1ec7n nay nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i \u1edf khu v\u1ef1c mi\u1ec1n B\u1eafc c\u0169ng \u1ee9ng d\u1ee5ng c\u00e1ch ch\u01a1i n\u00e0y v\u1edbi KQXSMB.<\/span><\/p>\n – \u0110\u1ec3 ch\u01a1i \u0111\u00e1 l\u00f4 b\u1ea1n c\u1ea7n ch\u1ecdn cho m\u00ecnh \u00edt nh\u1ea5t 2 con s\u1ed1 c\u00f3 2 ch\u1eef s\u1ed1, N\u1ebfu tr\u00fang t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 b\u1ea1n \u0111\u00e1nh th\u00ec th\u1eafng c\u00e1ch ch\u01a1i n\u00e0y. C\u00f3 2 c\u00e1ch ch\u01a1i \u0111\u00f3 l\u00e0:<\/span><\/p>\n + \u0110\u00e1 th\u1eb3ng l\u00e0 \u0111\u00e1nh 2 con l\u00f4 ho\u1eb7c nhi\u1ec1u h\u01a1n trong 1 t\u1ec9nh.<\/span><\/p>\n + \u0110\u00e1 xi\u00ean l\u00e0 \u0111\u00e1nh 2 con ho\u1eb7c nhi\u1ec1u h\u01a1n cho 2 t\u1ec9nh hay 3 t\u1ec9nh kh\u00e1c nhau, c\u00f9ng 1 ng\u00e0y g\u1ecdi l\u00e0 \u0111\u00e1 xi\u00ean. <\/span><\/p>\n – N\u1ebfu 1 trong 2 s\u1ed1 v\u1ec1 2 l\u1ea7n c\u0169ng kh\u00f4ng \u0111\u01b0\u1ee3c t\u00ednh th\u1eafng. N\u1ebfu c\u1ea3 2 s\u1ed1 v\u1ec1 2 l\u1ea7n th\u00ec ti\u1ec1n th\u01b0\u1edfng \u0111\u01b0\u1ee3c nh\u00e2n \u0111\u00f4i.<\/span><\/p>\n <\/p>\n – B\u1ea1n c\u00f3 th\u1ec3 \u0111\u00e1nh t\u00f9y \u00fd t\u1eeb 2 \u0111\u1ebfn 5 con trong m\u1ed9t l\u1ea7n ch\u01a1i, \u0111\u00e1 c\u00e0ng nhi\u1ec1u th\u00ec ti\u1ec1n c\u01b0\u1ee3c c\u00e0ng cao v\u00e0 ti\u1ec1n tr\u00fang c\u00e0ng l\u1edbn. Th\u01b0\u1eddng th\u00ec ng\u01b0\u1eddi mi\u1ec1n Nam th\u00edch ch\u01a1i \u0111\u00e1 2 con h\u01a1n nhi\u1ec1u con. <\/span><\/p>\n V\u00ed d\u1ee5: <\/span><\/p>\n – \u0110\u00e1nh l\u00f4 \u0111\u00e1 (\u0111\u00e1 th\u1eb3ng) con 40 – 21 t\u1ec9nh \u0110\u1ed3ng Nai th\u1ee9 4 tr\u00fang c\u1ea3 2 con th\u00ec b\u1ea1n tr\u00fang.<\/span><\/p>\n – \u0110\u00e1 xi\u00ean 2 \u0111\u00e0i ch\u00ednh T\u00e2y Ninh – An Giang con 50 – 05, t\u1ee9c l\u00e0 b\u1ea1n \u0111\u00e1nh con 50 cho \u0111\u00e0i T\u00e2y Ninh v\u00e0 05 cho \u0111\u00e0i An Giang. Khi con 50 xu\u1ea5t hi\u1ec7n trong \u0111\u00e0i T\u00e2y Ninh v\u00e0 05 trong \u0111\u00e0i An Giang th\u00ec b\u1ea1n th\u1eafng. <\/span><\/p>\n – V\u1edbi l\u00f4 xi\u00ean 2 c\u1ee7a mi\u1ec1n B\u1eafc khi tr\u00fang c\u1ea3 2 con b\u1ea1n ch\u1ec9 \u0111\u01b0\u1ee3c t\u1ef7 l\u1ec7 \u0103n 1:17. S\u1ed1 \u0111\u00e1 x\u1ed5 s\u1ed1 mi\u1ec1n Nam<\/u> c\u00f3 t\u1ef7 l\u1ec7 \u0103n th\u01b0\u1edfng cao h\u01a1n c\u00f3 th\u1ec3 1:34 v\u00ec c\u00f3 nhi\u1ec1u l\u00f4 h\u01a1n. C\u00f3 2 c\u00e1ch t\u00ednh ti\u1ec1n th\u00f4ng d\u1ee5ng nh\u1ea5t hi\u1ec7n nay:<\/span><\/p>\n – T\u00ednh ti\u1ec1n s\u1ed1 \u0111\u00e1 mi\u1ec1n Nam 1 ng\u00e0n tr\u00fang bao nhi\u00eau<\/span><\/p>\n + \u0110\u1ed1i v\u1edbi \u0111\u00e1 2 s\u1ed1: 1 ng\u00e0n tr\u00fang 34 ng\u00e0n. Khi 2 s\u1ed1 cu\u1ed1i c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c l\u00f4 c\u00f3 2 s\u1ed1 m\u00e0 b\u1ea1n mua. N\u1ebfu m\u1ed7i s\u1ed1 v\u1ec1 1 v\u1ec1 1 c\u1eb7p th\u00ec ti\u1ec1n th\u01b0\u1edfng s\u1ebd \u0111\u01b0\u1ee3c nh\u00e2n \u0111\u00f4i.<\/span> + \u0110\u1ed1i v\u1edbi \u0111\u00e1 3 s\u1ed1: 1 ng\u00e0n tr\u00fang 185 l\u1ea7n. Khi c\u1ea3 3 s\u1ed1 b\u1ea1n mua \u0111\u1ec1u xu\u1ea5t hi\u1ec7n trong 2 s\u1ed1 cu\u1ed1i c\u1ee7a c\u00e1c gi\u1ea3i k\u1ebft qu\u1ea3 XSMN. <\/span> + \u0110\u1ed1i v\u1edbi \u0111\u00e1 4 s\u1ed1: 1 ng\u00e0n tr\u00fang 970 l\u1ea7n. N\u1ebfu trong k\u1ebft qu\u1ea3 mi\u1ec1n Nam c\u00f3 c\u1ea3 4 con b\u1ea1n mua th\u00ec b\u1ea1n th\u1eafng c\u00e1ch \u0111\u00e1nh n\u00e0y.<\/span><\/p>\n V\u00ed d\u1ee5: <\/span><\/p>\n + \u0110\u00e1nh 5 ng\u00e0n 2 con 45 – 54 cho 2 \u0111\u00e0i V\u0169ng T\u00e0u – B\u1ebfn Tre, n\u1ebfu trong k\u1ebft qu\u1ea3 \u0111\u00e0i V\u0169ng T\u00e0u c\u00f3 45 v\u00e0 B\u1ebfn Tre c\u00f3 54 th\u00ec b\u1ea1n s\u1ebd tr\u00fang: 5.000 x 34 = 170.000<\/span><\/p>\n + \u0110\u00e1 3 con 11 – 21 – 91 \u0111\u00e0i S\u00f3c Tr\u0103ng 10 ng\u00e0g, n\u1ebfu k\u1ebft qu\u1ea3 v\u1ec1 c\u1ea3 3 s\u1ed1 th\u00ec b\u1ea1n nh\u1eadn \u0111\u01b0\u1ee3c: 10.000 x 185 = 1.850.000<\/span><\/p>\n + \u0110\u00e1 4 con 56 – 07- 42 – 89 \u0111\u00e0i \u0110\u1ed3ng Nai 50 ng\u00e0n, khi tr\u00fang c\u1ea3 4 s\u1ed1 b\u1ea1n s\u1ebd c\u00f3: 50.000 x 970 = 48.500.000 <\/span><\/p>\n <\/p>\n + \u0110\u00e1 l\u00f4 2 con: 1 \u0111i\u1ec3m s\u1ebd tr\u00fang v\u1edbi t\u1ef7 l\u1ec7 12.5 l\u1ea7n. Ti\u1ec1n th\u01b0\u1edfng khi b\u1ea1n tr\u00fang s\u1ebd l\u00e0 48.000 x 12.5 = 600.000, ti\u1ec1n l\u1eddi s\u1ebd l\u00e0 552 ng\u00e0n.<\/span><\/p>\n + \u0110\u00e1 l\u00f4 3 con: T\u1ee9c l\u00e0 3 c\u1eb7p 2 s\u1ed1 n\u00ean t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 12.5 x 3 = 37.5 l\u1ea7n. Khi k\u1ebft qu\u1ea3 v\u1ec1 c\u1ea3 3 con th\u00ec 1 \u0111i\u1ec3m s\u1ebd tr\u00fang: 48.000 x 37.5 = 1.800.000, ti\u1ec1n l\u1eddi l\u00e0 1.799.952. N\u1ebfu v\u1ec1 2 con s\u1ebd \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 \u0111\u00e1 2 s\u1ed1.<\/span><\/p>\n + \u0110\u00e1 l\u00f4 4 con: T\u1ee9c l\u00e0 6 c\u1eb7p 2 s\u1ed1 n\u00ean t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 12.5 x 6 = 75 l\u1ea7n. Khi tr\u00fang c\u1ea3 4 s\u1ed1, 1 \u0111i\u1ec3m b\u1ea1n s\u1ebd tr\u00fang: 48.000 x 75 = 3.600.000. N\u1ebfu tr\u00fang 3 s\u1ed1 s\u1ebd t\u00ednh ti\u1ec1n theo c\u00e1ch \u0111\u00e1 3 s\u1ed1, tr\u00fang 2 s\u1ed1 t\u00ednh ti\u1ec1n theo \u0111\u00e1 2 s\u1ed1. <\/span> + \u0110\u00e1 l\u00f4 5 con: L\u00e0 10 c\u1eb7p 2 s\u1ed1 n\u00ean t\u1ef7 l\u1ec7 s\u1ebd l\u00e0 12.5 x 10 = 125 l\u1ea7n. Khi tr\u00fang c\u1ea3 5 s\u1ed1, 1 \u0111i\u1ec3m b\u1ea1n s\u1ebd tr\u00fang: 48.000 x 125 = 6.000.000. Khi tr\u00fang 4 s\u1ed1, 3 s\u1ed1, 2 s\u1ed1 th\u00ec t\u00ednh ti\u1ec1n theo t\u1eebng lo\u1ea1i s\u1ed1 \u0111\u00e1 \u0111\u00f3.<\/span><\/p>\n + \u0110\u00e1 l\u00f4 2 con 03 – 46 \u0111\u00e0i C\u00e0 Mau 2 \u0111i\u1ec3m<\/u>, khi k\u1ebft qu\u1ea3 XSCM tr\u00fang c\u1ea3 2 con b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c: (48.000 x 2) x 12.5 = 1.200.000.<\/span> + \u0110\u00e1 l\u00f4 5 con 24 – 89 – 75 – 03 – 54, \u0111\u00e0i T\u00e2y Ninh 3 \u0111i\u1ec3m<\/u>, n\u1ebfu tr\u00fang c\u1ea3 5 con th\u00ec b\u1ea1n s\u1ebd nh\u1eadn \u0111\u01b0\u1ee3c: (48000 x 3) x 125 = 18.000.000. N\u1ebfu tr\u00fang ch\u1ec9 4 s\u1ed1 b\u1ea1n s\u1ebd c\u00f3: 144000 x 75 = 10.800.000, ch\u1ec9 tr\u00fang 3 s\u1ed1: 144000 x 37.5 = 5.400.000, ch\u1ec9 tr\u00fang 2 s\u1ed1: 144000 x 12.5 = 1.800.000.<\/span><\/p>\n B\u00e0i vi\u1ebft tr\u00ean ph\u00e2n t\u00edch s\u1ed1 \u0111\u00e1 mi\u1ec1n Nam l\u00e0 sao v\u00e0 2 c\u00e1ch t\u00ednh ti\u1ec1n s\u1ed1 \u0111\u00e1 th\u00f4ng d\u1ee5ng nh\u1ea5t hi\u1ec7n nay. Anh em c\u00f3 th\u1ec3 tham kh\u1ea3o th\u00f4ng tin \u0111\u1ec3 c\u00f3 th\u00eam ki\u1ebfn th\u1ee9c v\u1ec1 c\u00e1c c\u00e1ch ch\u01a1i x\u1ed5 s\u1ed1 mi\u1ec1n Nam m\u1edbi nh\u1ea5t <\/span><\/p>\n\n
S\u1ed1 \u0111\u00e1 mi\u1ec1n Nam l\u00e0 g\u00ec?<\/span><\/h2>\n
S\u1ed1 \u0111\u00e1 mi\u1ec1n Nam 1 ng\u00e0n tr\u00fang bao nhi\u00eau ti\u1ec1n<\/span><\/h2>\n
\n <\/span><\/p>\n
\n <\/span><\/p>\n– T\u00ednh ti\u1ec1n s\u1ed1 \u0111\u00e1 theo \u0111i\u1ec3m l\u00f4 (1 \u0111i\u1ec3m 48 ng\u00e0n):<\/span><\/h3>\n
\n <\/span><\/p>\nV\u00ed d\u1ee5:<\/span><\/h4>\n
\n <\/span><\/p>\nsoi c\u1ea7u cao c\u1ea5p mi\u1ec1n b\u1eafc<\/span><\/h3>\n